Mark M. answered 02/03/21
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
sin(2θ) - cosθ = 0
2sinθcosθ - cosθ = 0
cosθ(2sinθ - 1) = 0
cosθ = 0 or sinθ = 1/2
Solutions in the interval [0, 2π]:
cosθ = 0 when θ = π/2, 3π/2
sinθ = 1/2 when θ = π/6, 5π/6