Elyssa S. answered 02/01/21
2nd year PhD in Applied and Computational Mathematics
(f◦g◦h)(x)=f(g(h(x)))
We want to start from the inside and go out:
To find g(h(x)) we have to plug h(x) into g(x). So everywhere there is an x in g(x) we will in h(x):
g(h(x)) = 1/h(x) + 4 = 1/(1/x) + 4 = x+4
Now f(g(h(x))) = f(x+4) = sq(x+4) + 3, by plugging x+4 into the function f.