Nick F.

asked • 01/31/21

Show that f '(0) does not exist. Step 1 Using f '(x) = lim h→0 f(x + h) − f(x) h with x = 0, we have f '(0) = lim h→0 f(0 + h) − f(0) h

Nick F.

Let f(x) = x^(1/3)
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01/31/21

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