Brute force logic works fine here, since there are so few possible triplets:
4 options with x=y=1 + 3 options with x=1, y=2 + 2 options with x=1, y=3 + 1 option with x=1, y=4. By similar logic, x=2 gives 3+2+1 options, x=3 gives 2+1 options, and x=4 generates the 20th and final integer triplet.
Josh F.
01/31/21
Valerian 5.
is there's an exact answer?01/31/21