
RAFAH A. answered 01/30/21
Former College Instructor, Calculus and Algebra Tutor
x3 = - x
add x for both sides
x3 + x = -x + x
x3 + x = 0
x ( x2 + 1) = 0
x=0 or
x2 + 1 = 0
x2 = -1 , x = ±√ -1 = ± i
so we have three solutions one is real and two are imaginary.