Patrick B. answered 01/28/21
Math and computer tutor/teacher
f(x+h) = 1/[ 1 + sqrt(x+h)]
Then
f(x+h) - f(x) =
1/[ 1 + sqrt(x+h)] - 1/(1 + sqrt(x)) =
combines into a single fraction with LCD [(1+sqrt(x+h)) (1+ sqrt(x))]....
[ (1+sqrt(x)) - ( 1 + sqrt(x+h))]/ [ (1 + sqrt(x))(1 + sqrt(x+h))] =
The 1's cancel in the numerator and combines like terms....
[ sqrt(x) - sqrt(x+h)] / [ (1 + sqrt(x))(1 + sqrt(x+h))] =
Rationalizes the numerator by multiplying top and bottom by sqrt(x)+sqrt(x+h).....
[x - (x+h)]/[ (1 + sqrt(x))(1 + sqrt(x+h))(sqrt(x)+sqrt(x+h)] =
The x's cancel in the numerator and combines like terms....
-h / [ (1 + sqrt(x))(1 + sqrt(x+h))(sqrt(x)+sqrt(x+h)]
But...
the difference quotient used in the limit defintion is [ f(x+h)-f(x)] / h
So the H's CANCEL!!!
What remains is:
-1 / [ (1 + sqrt(x))(1 + sqrt(x+h))(sqrt(x)+sqrt(x+h)]
Finally, the limit h-->0 as h tends to zero is:
-1 / {2* [ 1 + sqrt(x)]^2 * sqrt(x)}
This is the derivative
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CHECKS by power rule/chain rule.....
y = (1 + x^(1/2))^(-1)
y' = (-1) * (1 + x^(1/2))^(-2) * (1/2)x^(-1/2)
= -1/ { 2 * [1 + x^(1/2)]^2*sqrt(x)}
which verify and proves the answer is correct