x(t) = sint - cost

x'(t) = v(t) = cost + sint (When does this equal zero?)

cost + sint = 0

cost = -sint

t = 3π/4 (cos(3π/4) = -sin(3π/4) = -√2/2)

a(t) = -sint + cost

a(3π/4) = -(√2/2) + -(√2/2)

=-2√2/2

=-√2

Katlyn K.

asked • 01/27/21For the position of a particle moving along the *x*-axis is given by . What is the acceleration of the particle at the point where the velocity is first equal to 0 ?

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x(t) = sint - cost

x'(t) = v(t) = cost + sint (When does this equal zero?)

cost + sint = 0

cost = -sint

t = 3π/4 (cos(3π/4) = -sin(3π/4) = -√2/2)

a(t) = -sint + cost

a(3π/4) = -(√2/2) + -(√2/2)

=-2√2/2

=-√2

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