find the area: x = 8y2, x = 1 + 7y2

Answer 1

Points of intersection: 8y² = 1 + 7y²; y² = 1; y = ±1;

Area A = ∫_-1¹(1 + 7y² - 8y²)dy = 2∫₀¹(1 - y²)dy = 2(y - y³/3) = 2(1 - 1/3) = 4/3