Henry R.

asked • 01/24/21

Question related to Complex Analysis

z^6 - 2z^3 - 8 = 0 using Polar Form and De Moivre theorem

1 Expert Answer

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Henry R.

Hi thank you for your time so does this mean that I will have to apply the polar form and de moivre on each bracketed terms? z^3=4 --------- find 3 roots using polar form and de moivre ;; z^3=-2 -------- find 3 roots using polar form and de moivre thank you.
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01/24/21

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