need help with this

Question

If the drop from the table height is 0.402 seconds, then how high was the table?

Answer 1

You can use the kinematic equation

X = X₀ + V₀T + 1/2AT²

It is convenient to use a coordinate system where the table top is zero and the positive direction is towards the ground. With this in mind we have the following values:

X = distance travelled by object when falling off table to the ground

X₀ = 0 (the object sitting on the table top)

V₀ = 0 (the object is at rest)

A = 9.8 m/s² (acceleration of gravity on Earth)

T = 0.402 s

Putting this all together we have:

1. X = 0m + (0m/s)(0.402s) + 1/2(9.8m/s²)(0.402s)²
2. X = 0 + 0 + 0.792 m
3. X = 0.792 m

The table is 0.792 meters high.

Let me know if this was helpful or if you need clarification.

Thank you,

David