We have lim x → ∞ e−x = 0 and lim x → ∞ 4 cos(3x) DNE. Hence lim x → ∞ (e−x + 4 cos(3x)) DNE.
Remark: If we change it a little bit, lim x → ∞ (ex + 4 cos(3x)) = ∞. Because ex → ∞ and 4 cos(3x) is bounded between -4 and 4 as x→∞.
Kate N.
asked 01/23/21Find the limit. (If the limit is infinite, enter '∞' or '-∞', as appropriate. If the limit does not otherwise exist, enter DNE.)
lim x → ∞ (e−x + 4 cos(3x))
We have lim x → ∞ e−x = 0 and lim x → ∞ 4 cos(3x) DNE. Hence lim x → ∞ (e−x + 4 cos(3x)) DNE.
Remark: If we change it a little bit, lim x → ∞ (ex + 4 cos(3x)) = ∞. Because ex → ∞ and 4 cos(3x) is bounded between -4 and 4 as x→∞.
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