Raymond B. answered 01/22/21
Math, microeconomics or criminal justice
let h= height of building
x = distance to the building after moving 50 feet closer
h/x = tan31 = about tan30 = .6
h/(50+x) = tan17 = close to .3
h= .6x = 15 + .3x
.3x = 15
x = 15/.3 = 50 degrees
h=.6x = .6(50) = 30 feet tall