Because the given function is increasing and concave up, I think we would have, from least to greatest:
Left-hand rectangles < Midpoint rectangles < Actual area < Trapezoids < Right-hand rectangles
5a , 4c , 3e , 1d , 2b
Nic C.
asked 01/20/21
Given f(x) > 0 with f ′ (x) > 0, and f ″ (x) > 0 for all x in the interval [0, 3] with f(0) = 0.1 and f(3) = 1, the left, right, trapezoidal, and midpoint rule approximations were used to estimate . The estimates were 0.8067, 0.9635, 1.0514, 1.0753 and 1.3439, and the same number of subintervals were used in each case. Match the rule to its estimate. (5 points)
1. | trapezoidal | ||||
2. | right endpoint | ||||
3. | actual area | ||||
4. | midpoint | ||||
5. | left endpoint | ||||
a. | 0.8067 | ||||
b. | 1.3439 | ||||
c. | 0.9635 | ||||
d. | 1.0753 | ||||
e. | 1.0514 |
Because the given function is increasing and concave up, I think we would have, from least to greatest:
Left-hand rectangles < Midpoint rectangles < Actual area < Trapezoids < Right-hand rectangles
5a , 4c , 3e , 1d , 2b
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.
Sreeram K.
your all wrong only 5 is a04/19/21