
Yefim S. answered 01/08/21
Math Tutor with Experience
v(t) = ∫(6t - 2)dt = 3t2 - 2t + C; v(0) = C = 3; so, v(t) = 3t2 - 2t + 3.
x(t) = ∫v(t)dt = ∫(3t2 - 2t + 3))dt = t3 - t2 + 3t + D, x(0) = D = 7;
so, x(t) = t3 - 3t2 + 3t + 7
Cao N.
asked 01/08/21Find the position function if
,
, and
.
Yefim S. answered 01/08/21
Math Tutor with Experience
v(t) = ∫(6t - 2)dt = 3t2 - 2t + C; v(0) = C = 3; so, v(t) = 3t2 - 2t + 3.
x(t) = ∫v(t)dt = ∫(3t2 - 2t + 3))dt = t3 - t2 + 3t + D, x(0) = D = 7;
so, x(t) = t3 - 3t2 + 3t + 7
Daniel B. answered 01/08/21
A retired computer professional to teach math, physics
Velocity v(t) is the indefinite integral of acceleration a(t).
v(t) = 3t² - 2t + C
The constant C is obtained from the constraint v(0) = 3, so C = 3.
v(t) = 3t² - 2t + 3
Position, x(t), is the indefinite integral of velocity v(t).
x(t) = t³ - t² + 3t + D
The constant D is obtained from the constraint x(0) = 7, so D = 7.
x(t) = t³ - t² + 3t + 7
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.