I need some help

Question

what is the slope of the tangent to the curve y³x + x²x² = 6 at (2, 1) is:

A. 5/2

B. 3/2

C -5/14

D. -3/14

Answer 1

y³ + 3y²y'x + 2x = 0, y' = - (y³ + 2x)/(3y²x)·; slope m at (2, 1): m = - (1 + 4)/3·1²2) = - 5/6

I think this answer right

Answer 2

I believe you got the statement of the problem wrong.

The point (2,1) does not lie on the curve y³x + x²x² = 6.

One guess at possible correction would be the curve y³x + x² = 6,

but its slope at (2,1) is -5/6.