Given: Integral from x=7 to x=5 of sqrt(3x+5) dx
Use U-sub to simplify
Note: Usually integrals start from a
lower value of x to a larger value of x.
Solution:
u = 3x + 5
du/dx = 3
du = 3 dx
x=7 ==> u = 3(7) + 5 = 26
x=5 ==> u = 3(5) + 5 = 20
I = The Integral
I = Integral from x=7 to x=5 of sqrt(3x+5) dx
I = (1/3) Integral from u=26 to u=20 of sqrt(u) du
Note: The (1/3) corrects for the additional 3 in du.
I = (1/3) [ (2/3)*u^(3/2) ] from u=26 to u=20
I = (1/3)(2/3) [ (26)^(3/2) - (20)^(3/2) ]
I = (2/9) [ (20)^(3/2) - (26)^(3/2) ]
I = -9.5848