Raymond B. answered 12/22/20
Math, microeconomics or criminal justice
c2-(c)^2 =-3/8 (c=cos2)
2c^2-1 -c^2 = -3/8
c^2 = 5/8
c = +sqr(5/8) = +0.79
w = 37.76 or 322.24, or 142.24 or 217.76 degrees
4 different angles between 0 and 360
Solve 8cos(2w)=8cos2(w)−3 for all solutions 0≤w<2π
Give your answers accurate as a list separated by commas
Raymond B. answered 12/22/20
Math, microeconomics or criminal justice
c2-(c)^2 =-3/8 (c=cos2)
2c^2-1 -c^2 = -3/8
c^2 = 5/8
c = +sqr(5/8) = +0.79
w = 37.76 or 322.24, or 142.24 or 217.76 degrees
4 different angles between 0 and 360
Yefim S. answered 12/22/20
Math Tutor with Experience
8cos(2w) = 8cos2w - 3;
8(2cos2w - 1) - 8cos2w + 3 = 0;
8cos2w - 5 = 0; 4cos(2w) - 1 = 0
cos(2w) = 1/4; 2w = cos-1(1/4) + 2πn; x = 1/2cos-1(1/4) + πn
or (2x) = 2π - cos-1(1/4) + 2πn; x = π - 1/2cos-1(1/4) + πn;
Verying n = 0, 1,2,.. we will get all solutions: n = 0: x = 1/2cos-1(1/4); x = π - 1/2cos-1(1/4)
n = 1: x = 1/2cos-1(1/4) + π, x = 2π - 1/2cos-1(1/4).
For n = 2, 3,.. we will get zeros outside of interval [0, 2π)
Mark M. answered 12/22/20
Mathematics Teacher - NCLB Highly Qualified
Would you know if my answer was inaccurate?
8 cos 2w = 8 cos2 w - 3
8 cos 2w - 8 cos2 w = -3
cos 2w - cos2 w = -3 / 8
2 cos2 w - 1 - cos2 w = -3 / 8
cos2 w - 1 = -3 / 8
cos2 w = 5 / 8
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