
Patrick B. answered 12/22/20
Math and computer tutor/teacher
F(x)=k(X+3)(x-2)(x+2)(x+5)
(1,12) --> f(1)=12
12= k*4*-1*3*6
12=-72k
K= -1/6

Mark M.
Substitute -1/6 for k in the first line.12/22/20
Moop M.
asked 12/22/20Find the polynomial function with real coefficients that has the following degree, and solutions and also passes through the point given. Degree: 4 Zeros: -3,2,-2,-5 Solution Point: (1,12)
Patrick B. answered 12/22/20
Math and computer tutor/teacher
F(x)=k(X+3)(x-2)(x+2)(x+5)
(1,12) --> f(1)=12
12= k*4*-1*3*6
12=-72k
K= -1/6
Mark M.
Substitute -1/6 for k in the first line.12/22/20
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Moop M.
can i make this a function?12/22/20