
Bradford T. answered 12/20/20
Retired Engineer / Upper level math instructor
Average temperature = (52+68)/2 = 60
Range is 52-68
Asin(B(x+C)) + D = y(x) range of sine is [-1,1]
Period = 2π/B = 24 hours --> B = π/12
A + D = 68
-A+D = 52
2D = 120 --> D = 60, A= 8
when x = 10, y(10) = 60
8sin((π/12)(10+C)) + 60 = 60 --> sin(θ) = 0 --> θ = 0
Thus (π/12)(10+C) = 0 ---> C = -10
y(x) = 58 = 8sin((π/2)(x-10)) + 60 --> sin((π/2)(x-10)) = -1/4 --> sin-1(-0.25) = 0.2527 = (π/2)(x-10)
x = 9.03 hours after midnight