
Bradford T. answered 12/17/20
Retired Engineer / Upper level math instructor
f(x) = xg(x2)
f '(x) = g(x2) + x(2x)g '(x2) = g(x2) + 2x2g '(x2) Using product and chain rules
f "(x) = (2x)g '(x2) + 4xg '(x2) + 2x2(2x)g "(x2)
= 2xg '(x2) + 4xg '(x2) + 4x3g"(x2)
= 6g '(x2) + 4x3g "(x2)