Jon P. answered 02/23/15
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Notice that the powers of the x terms are multiples of 5.
So do a substitution to make it easier. Let y = x5.
So the polynomial becomes 9y2 + 12y + 4
Now factor this as (3y + 2) (3y + 2) = (3y + 2)2
Now substitute x5 back in for y and you get: (3x5 + 2)2