Let f(x) = ex tan x. (a) Find f′(x) (b) Find the slope of the line tangent to the graph of f(x) = ex tanx at the point (1, e tan(1))

Answer 1

f(x) =e^x tan x. So f'(x) = e^x tan x +e^x sec² x. The slope at the point (1, e tan(1)) is f'(1) = e tan(1) +e sec²(1).