Tom N. answered 12/16/20
Strong proficiency in elementary and advanced mathematics
Let f(x) =x g(x2). So f'(x) = g(x2) + 2x2g'(x2). f"(x)= 2xg'(x2) +4x g'(x2) +4 x3 g"(x2). So f"(x)= 6 x g'(x2) + 4 x3 g"(x2).
Ash L.
asked 12/15/20If g is twice differentiable function and f(x) = xg(x2) find f′′(x) in terms of g,g′, ′′
and g . Simplify your answer as much as possible. (Hint: to say that g is twice differentiable means both g′ and g′′ exist.)
Tom N. answered 12/16/20
Strong proficiency in elementary and advanced mathematics
Let f(x) =x g(x2). So f'(x) = g(x2) + 2x2g'(x2). f"(x)= 2xg'(x2) +4x g'(x2) +4 x3 g"(x2). So f"(x)= 6 x g'(x2) + 4 x3 g"(x2).
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