Tom K. answered 12/16/20
Knowledgeable and Friendly Math and Statistics Tutor
r2sinθdrdθdφ = dxdydz
As x2 + y2 +z2 <= 25, r <= 5.
z = r cosθ. Thus, above the xy plane means z > 0, and z <= √(x2 + y2), so π/4 <= θ < π/2.
Now, we can integrate
∫02π∫π/4π/2∫05 r2sinθdrdθdφ =
∫02π∫π/4π/21/3r3sinθ|05 dθdφ =
∫02π∫π/4π/2∫05 125/3sinθ dθdφ =
125/3∫02π∫-cosθ|π/4π/2 dφ =
125√2/6 ∫02π dφ =
125√2/6 φ |02π =
125√2/3 π