Daniel B. answered 12/13/20
A retired computer professional to teach math, physics
Let,
s1 = 400 miles be the distance travelled with the wind,
s2 = 320 miles be the distance travelled against the wind,
vw = 27 mph be the velocity of the wind with respect to the ground,
vp (to be found) be the velocity of the plane with respect to the air,
or equivalently the velocity of the plane with respect to the ground in still air.
With the wind, the velocity of the plane with respect to the ground is
vp+vw
Against the wind, the velocity of the plane with respect to the ground is
vp-vw
In general, time traveled is the ration between distance travelled and average velocity, i.e.,
s/v
The statement that the plane took the same time to travel both distances is expressed by
s1/(vp+vw) = s2/(vp-vw)
From that we can solve
vp = vw(s1+s2)/(s1-s2)
Substituting actual numbers
vp = 27 x 720/80 = 243 mph