write an equation that is perpendicular to 3x-5y=5 and passes through the point (9,-14)

Answer 1

5y = 3x -5

y = (3/5)x -1 has slope = 3/5. A perpendicular line has slope = the negative inverse of 3/5 = -5/3. change the sign and flip the fraction upside down.

y=-(5/3)x + b where b = the y intercept. To calculate b, plug in the point with x=9 and y=-14

-14 = -(5/3)(9) + b

b = -14 + 15 = 1

y=-(5/3)x + 1 or

3y= -5x + 3 or

5x+3y = 3 is the equation of a perpendicular line through the given point (9,-14)