Raymond B. answered 12/10/20
Tutor
5
(2)
Math, microeconomics or criminal justice
f'(x) =24x^2 -382 =2
24x^2 = 384
x^2 = 384/24 = 64/4= 16
x = 4,-4
Derick M.
asked 12/10/20For what values of x is the tangent line of the graph of f(x)=8x^3 - 382x + 24
parallel to the line y=2x + 0.1 ?
x =
stuck please help
Raymond B. answered 12/10/20
Math, microeconomics or criminal justice
f'(x) =24x^2 -382 =2
24x^2 = 384
x^2 = 384/24 = 64/4= 16
x = 4,-4
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