Average value = 1/(b-a) integral (from a to b) f(x) dx. [a,b], so b=2 and a=-1.
I get -9/12
Shai M.
asked 12/09/20What is the average value of f(x)=x−x^3 on [−1,2]
Average value = 1/(b-a) integral (from a to b) f(x) dx. [a,b], so b=2 and a=-1.
I get -9/12
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