The series for ln(1+x) = x - (x2/2)-(x3/3) + terms of higher order
The given expression then becomes -1/3 + terms of higher order
Therefore the limit is -1/3.
Kevin S.
asked 12/08/20The series for ln(1+x) = x - (x2/2)-(x3/3) + terms of higher order
The given expression then becomes -1/3 + terms of higher order
Therefore the limit is -1/3.
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