Equation that relates the volume and height of a cone with a radius of 3

Question

Write down an equation that relates the two quantities described. Then use implicit differentiation to obtain a relationship between the rates at which the quantities change over time. The volume V and height h of a cone with a fixed radius of 3 units.

Answer 1

V=(π/3)r²h = 3πh

dV/dt = 3π dh/dt

Don't really need implicit differentiation for this simple relationship, just straight differentiation.