Tom K. answered 12/07/20
Knowledgeable and Friendly Math and Statistics Tutor
f(0) = 0
f(1) =0
f(x) is continuous on [0, 1] and differentiable on (0,1).
Thus, there exists a c in (0, 1) such that f'(c) = 0
f'(x)= 1 - 1/4 x-3/4
1 = 1/4 x-3/4
4 = x-3/4
4-4/3 = x
1/44/3 = x
1/28/3 = x
21/3/8 =x