Find the particular solution that satisfies the initial condition. (Enter your solution as an equation.)

Question

Differential Equation Initial Condition

yy'-22e^x=0 y(0)=11

can you show the steps in solving this?

Answer 1

y(dy/dx) = 22e^x Variables are separable!

y dy = 22 e^x dx

y²/2 = 22 e^x + C

11 = 22 + C => C=-11

y²/2 = 22 e^x - 11

You may need to write this in a different form, although it is quite correct as it stands.

Note that y is not a function of x unless you restrict domain.