Raymond B. answered 12/03/20
Math, microeconomics or criminal justice
.04 x 1900 = 76
4% probability of a false positive
But that assumes the false positive and false negative rates are the same. Generally, they aren't. With more information, you could use Bayes' Theorem to solve this problem.
Bayes Theorem is P(p/~D)P(~D) = P(~D/p)P(p)
Let P(p/~D) = the probability of testing positive for drugs when no drugs were used = false positive
P(~D) = probability of not using drugs
P(p) = probability of a positive test
P(~D/p) = probability of not using drugs given a positive test result for drugs
P(p/~D) = P(~D/p)P(p)/[(P(~D/p)P(p) + P(~D/~p)P(~p)]
The test can be reliable in two different ways, few false positives or few false negatives. The two errors generally are not the same.