Raymond B. answered 03/18/21
Math, microeconomics or criminal justice
Triangle area = 6(6)/2 = 18
square cross sections are vertical slices varying up to 3sqr2, the hypotenuse of the triangle base
for each square cross section x=y and z=xsqr2 = height. triangular area = x^2/2 for each cross section
use the vertical axis as z for height
integrate x^2/2(x)sqr2 = (sqr2)/2)(x^3) evaluated from 0 to 3
= sqr2 x^4/8= (81/8)sqr2 = about 14.32 cubic units
It's hard to visualize the cross sections or how the problem intends them. But maybe 14.32 is right.