Michael M. answered 12/03/20
Math, Chem, Physics, Tutoring with Michael ("800" SAT math)
So we use parametric equations for the path. y = t, x = t2 + 4. We can put this in a vector.
r(t) = t2+4 i + t j
Find F(r(t))
F(r(t)) = 4*(t2 + 4) * t i + 3 j = 4t3 + 16t i + 3 j
Next we find r'(t) by taking derivatives of the component vectors of r(t) with respect to t
r'(t) = 2t i + 1 j
Plug it into the equation: ∫C F • dr
F • dr is (4t3 + 16t)(2t) + 3(1) = 8t4 + 32t2 + 3
Now get the interval:
y = t and y goes from 0 to 1. Therefore t goes from 0 to 1
Plug into the line integral equation and solve
∫01 8t4 + 32t2 + 3 = 8/5 + 32/3 + 3 = 229/ 15