Need help with math question!!!

Question

Find the axis of symmetry for the parabola

Answer 1

if the equation is of the form y = a(x-h)² + k then given

y = 1/16 * (x-2)² -1

k = -1, h = 2 and a = 1/16 and from a prior question the focus is (2,3).

This gives that the axis of symmetry is the line x = 2. You can see this by noticing that the focus is always above the vertex of the parabola or in other words, it shares the x-coordinate with the vertex.

The axis of symmetry will run parallel with the y-axis and at right angles to the x-axis.

Answer 2

When a parabola is written as y=a(x-h)^2+k the vertex of the parabola is the point with the coordinates (h,k) and the axis of symmetry is x=h.

I think you can take it from here and figure it out the axis of symmetry for your parabola y=1/16(x-2)^2-1

Answer 3

So the equation of this parabola is actually already written in vertex form, which makes this simpler for you!

Vertex form is written as: y=a(x-h)^2+k OR y-k = a(x-h)^2. The latter is the format you have. Regardless, in vertex form, the axis of symmetry is just the line x = h. So, for your problem, the AOS is the equation x = 2.