Find the absolute maximum and absolute minimum values of f (x) = ^3√ t(8 − t) on [0, 8].

Answer 1

f(t) =[t(8 - t)]^1/3_{; f'(t) = 1/3[t(8 - t)]}^-2/3_{(8 - 2t) = 0, t = 4 is 1st critical point and t = 0 and t = 8 other critical points.}

_{f(4) = 2}^4/3 _{is maximum}

_{f(0) = f(8) = 0 2 minimums}