Suppose the integral from 2 to 8 of g of x, dx equals 13 , and the integral from 6 to 8 of g of x, dx equals negative 3 , find the value of 2 plus the integral from 2 to 6 of g of x, dx

Question

Suppose  , and  , find the value of 

A) 16

B) 18

C) 8

D) 32

Answer 1

We first calculate that (integral of g(x) from 2 to 6 dx)=16 and hence the required expression equals 2+16=18.