an = 7 + 3(n-1)
49 = 7 + 3(n-1) => n=15
∑an = 15*7 +3∑n - 3∑1 =105 + 3∑n - 45 = 60 + ∑n
where the ∑ runs from 1 to n
This is not exactly the form you question requests, but it is correct. However,
A = 15 and B = 7+3(n-1)
Joe S.
asked 11/23/20Write the sum using sigma notation:
A= __________________
B= __________________
an = 7 + 3(n-1)
49 = 7 + 3(n-1) => n=15
∑an = 15*7 +3∑n - 3∑1 =105 + 3∑n - 45 = 60 + ∑n
where the ∑ runs from 1 to n
This is not exactly the form you question requests, but it is correct. However,
A = 15 and B = 7+3(n-1)
The answer is B=3k+4 and A=15.
Mark M. answered 11/23/20
Mathematics Teacher - NCLB Highly Qualified
49 = 7 + 3(n - 1)
15 = n
A = 15
B = 7 + 3(n - 1)
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