
Justin R. answered 11/23/20
Ph.D. in Geophysics with 30 Years of Teaching Experience
I hope this wasn't how the question was posed. If it was, boo on your teacher.
Because this is a definite integral, the only "x" here is in the integral bound. In other words, you can rewrite this as (e.g.):
g(x) = integral(1 to x) of s^2/sqrt(s^2+4)ds
The x inside the integral is a dummy variable of integration.
As a result, the answer is: dg/dx = x^2/sqrt(x^2+4)