A transformation P is a projection if it is idempotent: P2=P.
P is orthogonal if in addition Pt = P.
So, to show that the given P is an orthogonal projection, we need to verify that both of these are true.
Try applying the transpose to the expression for P given in part 1a, and verify that Pt=P. For this it is helpful to refer to algebraic properties of the transpose operation. Then show that multiplying P by itself gives you an expression that reduces to P.
P2 = P*P = (A(AtA)-1At) * (A(AtA)-1At)
Can you see anything in the middle that simplifies when you move parentheses around?
Question 2 follows in a similar fashion.
1b) Set A = u and appeal to part 1a. Note that since u is a nx1 column vector, ut is a 1xn row vector, so utu is a 1x1 matrix. Moreover, if we look at this matrix product in coordinates, we see
utu = u12 + ... + un2
This is just 1, since we've assumed that u is a unit vector. This tells us that for A=u, the product AtA = utu is invertible. Now apply part (1a).