
Mike D. answered 11/23/20
Effective, patient, empathic, math and science tutor
Consider a cuboid of water, height dh, at distance h below the ground
Volume of the water is 30 x 20 x dh = 600 dh
Mass of this water = 62.3 x 500 dh = 31150 dh (lbs)
1 kg = 2.2 lbs, so this is 14159 dh kg
1 ft = 0.3 m approximately
We need to raise this water through h feet = 0.3 h metres
So work done = force x distance = mgh = 14159 x 9.81 x 0.3 h = 41670h J
So you just need to integrate this from h=3 to h=6
Giving [20835 h2] between limits 3 and 6, giving total work of 20835 x (36 - 9) = 562545 J