Daniel B. answered 11/30/20
A retired computer professional to teach math, physics
We will need the first two derivatives of p:
p(x) = 5x³ - 12x² - 3750x + 180
p'(x) = 15x² - 24x - 3750
p"(x) = 30x - 24
(a) The critical points of a differentiable functions, like p,
are those where the derivative is 0:
15x² - 24x - 3750 = 0
5x² - 8x - 1250 = 0
x = (8 +- sqrt(64 + 4 x 5 x 1250))/(2 x 5)
= (4 +- sqrt(16 + 5 x 1250))/5
= 16.63 and -15.03
(b) The problem statement does not limit us to any domain,
so we consider all real values x.
p(x) goes to -infinity when x goes to -infinity and
p(x) goes to +infinity when x goes to +infinity.
Therefore the function has no extreme values.
(c) An inflexion point occurs where the second derivative is 0:
30x - 24 = 0
x = 0.8
(d) The interesting features are at 16.63, -15.03, 0.8.
The interval [-20, +20] looks nice to me.
(e) This platform does not allow me to attach a file.