
Patrick B. answered 11/20/20
Math and computer tutor/teacher
Here is the parabola that passes through those 3 points:
y = Ax^2+Bx+C
(0,2) ---> C = 2 ---> y = Ax^2+Bx+2
(7,4) ---> 49A + 7B + 2 = 4
49A + 7B = 2
(8,-4) ---> 64A + 8B +2 = -4
64A + 8B = -6
32A + 4B = -3
49A + 7B = 2
32A + 4b = -3
Elimination: -4 * eq1 and 7*eq2
-196A + -28B = -8
224A + 28B = -21
28A = -29
A = -29/28
49 ( -29/28) + 7B = 2
(7/4)(-29) + 7B = 2
-203/4 + 7B = 2
7B = 2 + 203/4 = 8/4+203/4 = 211/4
B = 211/28
y = (-29/28)x^2 + (211/28)x + 2
integrate that function