A bag contains 39 U.S. quarters and eleven Canadian quarters. If four quarters are randomly picked from the bag, what is the probability of getting at least one Canadian quarter?

Question

Answer should be rounded to one decimal place.

Answer 1

Key for this kind of problem is to understand that P(at least one CQ) = 1 - P(no CQ)

P(no CQ) can be obtained by counting or multiplying the probabilities of getting only AQ 4 times without replacement:

(39/50)(38/49)(37/48)(36/47)

Good luck!