Jon S. answered 11/15/20
Patient and Knowledgeable Math and English Tutor
Two dice are numbered 1 through 8
64 possible combinations (sums in the middle)
1 2 3 4 5 6 7 8
1 2 3 4 5 6 7 8 9
2 3 4 5 6 7 8 9 10
3 4 5 6 7 8 9 10 11
4 5 6 7 8 9 10 11 12
5 6 7 8 9 10 11 12 13
6 7 8 9 10 11 12 13 14
7 8 9 10 11 12 13 14 15
8 9 10 11 12 13 14 15 16
6 of those sums are greater than 13 (14, 14, 15, 14, 15, 16)
so the probability of the sum of the two die being greater than 13 is 6/64 = 3/32