
Mike D. answered 11/13/20
Effective, patient, empathic, math and science tutor
For the first
435 C 32 x 0.0775^32 x (1-0.0775) ^ 403
For the second
Approximate the binomial distribution with a normal here
n = 435
p = 0.0775
q = 1-p = 0.9225
B(n,p) is approximately N(np, √npq)
So N (33.7125, 5.5767)
So you need p (X<30).
On a TI-84
2nd vars
normalcdf
lower -1e99
upper 30
mean 33.7125
sd 5.5767
answer 0.253
(You can also calculate p (X=0) + ... P(X=29) to get an exact answer where
p (X=n) = 435 C n x 0.0775^n x 0.9225^(435-n)
Lillian K.
What is the answer for 1. I don’t have a calculator...11/13/20