Mike D. answered 11/12/20
Effective, patient, empathic, math and science tutor
p(0) = 0.33^4
p(1) = 4 x 0.67 x 0.33^3
p(2) = 4 C 2 x 0.67^2 x 0.33 ^ 2 = 6 x 0.67^2 x 0.33^2
p(3) = 4 x 0.67^3 x 0.44
p(4) = 0.67^4
a) p(2)
b) 1 - p(0)
c) p(3) + p(4)
Esther N.
asked 11/12/20Drug A has probability of 0.67 of curing COVID-19 whenever it is administered. If drug A is administered 4 times, find the probability that drug A will cure COVID-19 when administered;
a) Exactly 2 times
b) At least 1 times
c) More than half of the times
Mike D. answered 11/12/20
Effective, patient, empathic, math and science tutor
p(0) = 0.33^4
p(1) = 4 x 0.67 x 0.33^3
p(2) = 4 C 2 x 0.67^2 x 0.33 ^ 2 = 6 x 0.67^2 x 0.33^2
p(3) = 4 x 0.67^3 x 0.44
p(4) = 0.67^4
a) p(2)
b) 1 - p(0)
c) p(3) + p(4)
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