
Joaquin B. answered 11/12/20
Chemical Engineer with 10+ years teaching/tutoring Calculus
I believe if you integrate R(t) in the interval from 0 to 6 years you will obtain the number of barrels produced in 6 years. So let’s start the integration:
∫((700t2)/(t3 + 32) + 5,t,0,6)
*the integral notation used is what a TI-89 or better uses to integrate.
I will integrate (700t2)/(t3 + 32) by using substitution. Let u = t3 + 32 and du = 3t2dt. The substitution will change the first part of the integral ∫(700t2)/(t3 + 32) dt into: ∫(700)/(3u) du = 700/3 ln u
Reversing the substitution yields:
700/3ln(t3 + 32) + 5t which needs to be evaluated in the interval [0,6]. Evaluation on this interval will result in the following expression:
700/3ln((63 + 32)/(03 + 32)) + 5(6)
700/3ln(248/32) + 30
700/3(2.048) + 30 ≈ 508 thousand barrels