Raymond B. answered 11/11/20
Math, microeconomics or criminal justice
width = 2sq3
height = 6
max area = 12sqr3
A = xy =x (9-x^2) = 9x - x^3
A' = 9 -3x^2
x^2 = 3
x = sqr3
y = 6
Anna Z.
asked 11/11/20A rectangle is inscribed with its base on the x-axis and its upper corners on the parabola y=9−x2. What are the dimensions of such a rectangle with the greatest possible area?
width=
height=
Raymond B. answered 11/11/20
Math, microeconomics or criminal justice
width = 2sq3
height = 6
max area = 12sqr3
A = xy =x (9-x^2) = 9x - x^3
A' = 9 -3x^2
x^2 = 3
x = sqr3
y = 6
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